{"id":18091,"date":"2024-03-06T10:45:36","date_gmt":"2024-03-06T10:45:36","guid":{"rendered":"https:\/\/soicau4015.minhngocxoso.com\/?p=18091"},"modified":"2024-03-06T10:45:36","modified_gmt":"2024-03-06T10:45:36","slug":"soi-cau-la-gi-soi-cau-xo-so-mien-bac","status":"publish","type":"post","link":"https:\/\/loxiendepnhat.com\/soi-cau-la-gi-soi-cau-xo-so-mien-bac\/","title":{"rendered":"soi c\u1ea7u l\u00e0 g\u00ec ? soi c\u1ea7u x\u1ed5 s\u1ed1 mi\u1ec1n b\u1eafc"},"content":{"rendered":"\n
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C\u00f3 nhi\u1ec1u b\u1ea1n m\u1edbi ch\u01a1i l\u00f4 \u0111\u1ec1 ho\u1eb7c \u0111\u01b0\u1ee3c nghe nhi\u1ec1u ng\u01b0\u1eddi nh\u1eafc t\u1edbi: soi c\u1ea7u l\u00f4, soi c\u1ea7u \u0111\u1ec1. M\u00e0 kh\u00f4ng hi\u1ec3u soi c\u1ea7u l\u00e0 g\u00ec. Th\u00ec h\u00f4m nay ad s\u1ebd t\u00ecm hi\u1ec3u v\u00e0 xin gi\u1ea3i th\u00edch chi ti\u1ebft t\u1edbi c\u00e1c b\u1ea1n \u0111\u1ecbnh ngh\u0129a soi c\u1ea7u l\u00f4 l\u00e0 g\u00ec, c\u00e1c v\u1ecb tr\u00ed c\u1ea7u l\u00f4, T\u1ed5ng s\u1ed1 c\u1ea7u l\u00f4 c\u1ea7n soi s\u00e9t. V\u00e0 c\u00e1c ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4, b\u00ed k\u00edp soi c\u1ea7u \u0111\u1ec1 ph\u1ed5 bi\u1ebfn hi\u1ec7n nay \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u b\u1ea1n s\u1eed d\u1ee5ng.<\/p>\n\n\n\n
Soi C\u1ea7u l\u00f4<\/strong> ch\u00ednh l\u00e0 s\u1ef1 k\u1ebft h\u1ee3p gi\u1eefa hai v\u1ecb tr\u00ed b\u1ea5t k\u00ec tr\u00ean b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1. Nh\u01b0 v\u1eady vi\u1ec7c soi c\u1ea7u l\u00f4 l\u00e0 soi x\u00e9t di\u1ec5n bi\u1ebfn c\u1ee7a vi\u1ec7c gh\u00e9p hai v\u1ecb tr\u00ed trong b\u1ea3ng k\u1ebft qu\u1ea3 trong nhi\u1ec1u ng\u00e0y li\u00ean ti\u1ebfp.<\/p>\n\n\n\n S\u1ed1 V\u1ecb tr\u00ed v\u00e0 t\u1ed5ng s\u1ed1 c\u1ea7u l\u00f4 l\u00e0 bao nhi\u00eau?<\/strong><\/p>\n\n\n\n \u2013<\/strong> Khi soi c\u1ea7u mi\u1ec1n b\u1eafc<\/strong> b\u1ea1n ph\u1ea3i bi\u1ebft c\u00f3 bao nhi\u00eau v\u1ecb tr\u00ed trong b\u1ea3ng k\u1ebft qu\u1ea3. \u1ede gi\u1ea3i \u0111\u1eb7c bi\u1ec7t<\/strong>, 1, 2, gi\u1ea3i 3 c\u00f3 5 s\u1ed1. V\u1eady 10 gi\u1ea3i s\u1ebd c\u00f3 50 s\u1ed1.<\/p>\n\n\n\n \u2013<\/strong> 40 s\u1ed1 g\u1ed3m 4 gi\u1ea3i t\u01b0 v\u00e0 6 gi\u1ea3i n\u0103m m\u1ed7i gi\u1ea3i c\u00f3 4 s\u1ed1, 3 gi\u1ea3i 6 v\u1eady c\u00f3 9 s\u1ed1. Gi\u1ea3i 7 c\u00f3 4 gi\u1ea3i, m\u1ed7i gi\u1ea3i 2 s\u1ed1 l\u00e0 8 s\u1ed1.<\/p>\n\n\n\n \u2013<\/strong> T\u1eeb \u0111\u1ecbnh ngh\u0129a v\u1ec1 c\u1ea7u l\u00f4<\/strong> ta c\u00f3 th\u1ec3 hi\u1ec3u r\u1eb1ng, \u1edf m\u1ed7i v\u1ecb tr\u00ed c\u00f3 th\u1ec3 gh\u00e9p \u0111\u01b0\u1ee3c 106 v\u1ecb tr\u00ed kh\u00e1c nhau \u0111\u1ec3 t\u1ea1o th\u00e0nh 106 c\u1ea7u l\u00f4<\/strong> kh\u00e1c nhau. Theo ph\u00e9p t\u00ednh giai th\u1eeba th\u00ec t\u1ed5ng s\u1ed1 c\u1ea7u l\u00f4<\/strong> gh\u00e9p 2 v\u1ecb tr\u00ed kh\u00e1c nhau l\u00e0 [(107!)\/(107-2)! X 2!] = 5671.<\/p>\n\n\n\n \u2013 <\/strong>Th\u00eam m\u1ed9t \u0111i\u1ec1u ng\u01b0\u1eddi ch\u01a1i c\u1ea7n ch\u00fa \u00fd l\u00e0 c\u00e1c v\u1ecb tr\u00ed kh\u00f4ng ch\u1ec9 gh\u00e9p v\u1edbi v\u1ecb tr\u00ed kh\u00e1c m\u00e0 c\u00f3 th\u1ec3 gh\u00e9p \u0111\u01b0\u1ee3c v\u1edbi ch\u00ednh n\u00f3 \u0111\u1ec3 c\u00f3 c\u1eb7p s\u1ed1 k\u00e9p. Nh\u01b0 v\u1eady ta l\u1ea1i c\u00f3 th\u00eam 107 c\u1ea7u l\u00f4<\/strong> s\u1ed1 k\u00e9p n\u1eefa \u0111\u1ec3 \u0111\u00e1nh l\u00f4 \u0111\u1ec1<\/strong>.<\/p>\n\n\n\n \u2013<\/strong> Ngo\u00e0i ra c\u00f2n c\u00f3 c\u00e1ch gh\u00e9p t\u1eebng v\u1ecb tr\u00ed trong b\u1ea3ng k\u1ebft qu\u1ea3 v\u1edbi c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean t\u1eeb 0-9, c\u00f3 th\u00eam 107\u00d710=1070 c\u1ea7u l\u00f4<\/strong> n\u1eefa. V\u1edbi c\u00e1ch gh\u00e9p n\u00e0y nhi\u1ec1u tr\u01b0\u1eddng h\u1ee3p ra c\u1ea7u l\u00f4<\/strong> c\u1ef1c t\u1ed1t.<\/p>\n\n\n\n => V\u1eady t\u1ed5ng l\u1ea1i ta c\u00f3 5671 + 107 + 1070 = 6848 c\u1ea7u l\u00f4<\/strong><\/p>\n\n\n\n M\u1ed7i m\u1ed9t ng\u01b0\u1eddi ch\u01a1i \u0111\u1ec1u c\u00f3 nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 \u0111\u1ec1<\/strong> kh\u00e1c nhau, tuy nhi\u00ean c\u0169ng c\u00f3 nhi\u1ec1u ph\u01b0\u01a1ng ph\u00e1p ph\u1ed5 bi\u1ebfn nh\u01b0 sau:<\/em><\/p>\n\n\n\n \u2013<\/strong> N\u00ean t\u00ecm c\u00e1c c\u1ea7u l\u00f4 \u0111\u1eb9p<\/strong> kh\u00f4ng g\u00e3y c\u1ee5 th\u1ec3 c\u1ea7u ch\u1ea1y t\u1ea7m > 4,5 ng\u00e0y tr\u1edf l\u00ean b\u1eaft tay v\u00e0o nu\u00f4i (N\u00ean s\u1eed d\u1ee5ng k\u00e8m theo b\u1ecdc l\u00f3t \u0111\u1ec3 ch\u1eafc \u0103n h\u01a1n \u2013 Theo ti\u1ec1n thi\u00ean b\u00e1t qu\u00e1i, h\u1eadu thi\u00ean b\u00e1t qu\u00e1i, ch\u1ec9 c\u00f3 08 qu\u1ebb t\u1eeb 1 \u0111\u1ebfn 8, s\u1ed1 9 quy v\u1ec1 1, s\u1ed1 0 quy v\u1ec1 8. 0 l\u00f3t 8, 8 l\u00f3t 0, 1 l\u00f3t 9, 9 l\u00f3t 1 kh\u00f4ng k\u1ec3 h\u00e0ng tr\u0103m, h\u00e0ng ch\u1ee5c, h\u00e0ng \u0111\u01a1n v\u1ecb.<\/p>\n\n\n\n V\u00ed d\u1ee5<\/em>: B\u1eaft s\u1ed1 228 \u2014 > l\u00f3t 220, 208 \u2014 > l\u00f3t 280, 899 \u2014 > l\u00f3t 011, 819\u2014 > l\u00f3t 091<\/em><\/p>\n\n\n\n \u2013<\/strong> Nh\u1eefng con v\u1ec1 2 nh\u00e1y n\u00ean \u0111\u1ec3 c\u00e1ch 1 h\u00f4m r\u1ed3i \u0111\u00e1nh c\u1eb7p l\u00f4 \u0111\u00f3.<\/p>\n\n\n\n \u2013<\/strong> Con \u0111\u1ea7u ti\u00ean c\u1ee7a gi\u1ea3i 4 \u0111\u1ed1i v\u1edbi Mi\u1ec1n B\u1eafc<\/strong> v\u00e0 gi\u1ea3i 6 \u0111\u1ed1i v\u1edbi Mi\u1ec1n Nam<\/strong> v\u00e0 Mi\u1ec1n Trung<\/strong>: b\u1ea5t k\u00ec con n\u00e0o k\u00e8m theo s\u1ed1 0 \u1edf \u0111\u1ea7u th\u00ec h\u00f4m sau s\u1ebd v\u1ec1 l\u1ea1i con sau s\u1ed1 0 \u0111\u00f3<\/p>\n\n\n\n +) \u0110\u00e0 N\u1eb5ng<\/strong> \u2013 Mi\u1ec1n Trung<\/strong> gi\u1ea3i 6 c\u00f3: 0123 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 12<\/em><\/p>\n\n\n\n +) Mi\u1ec1n b\u1eafc<\/strong> gi\u1ea3i 4 c\u00f3: 0345 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 34<\/em><\/p>\n\n\n\n L\u01b0u \u00fd: Nu\u00f4i khung 2 ng\u00e0y nh\u00e9. N\u1ebfu h\u00f4m sau l\u1ea1i ti\u1ebfp t\u1ee5c xu\u1ea5t hi\u1ec7n con c\u00f3 s\u1ed1 0 \u1edf \u0111\u1ea7u th\u00ec h\u00f4m sau l\u1ea1i ch\u01a1i theo con ng\u00e0y h\u00f4m \u0111\u00f3.<\/em><\/p>\n\n\n\n \u2013 L\u00f4 3 ng\u00e0y theo \u201cd\u1ea1ng s\u1ed1\u201d<\/strong>: C\u00e1c b\u1ea1n ch\u00fa \u00fd th\u1ea5y h\u00f4m n\u00e0o \u1edf gi\u1ea3i 4 s\u1ed1 c\u00f3 d\u1ea1ng ch\u1ec9 c\u00f3 2 \u0111\u01a1n v\u1ecb gh\u00e9p n\u00ean gi\u1ea3i 4 s\u1ed1 \u0111\u00f3 th\u00ec ta ch\u01a1i c\u1eb7p \u0111\u00f3 trong 3 h\u00f4m, th\u00f4ng th\u01b0\u1eddng c\u0169ng hay v\u1ec1 ng\u00e0y th\u1ee9 2 (V\u00ed d\u1ee5: Soi c\u1ea7u \u0110\u00e0 N\u1eb5ng <\/strong>gi\u1ea3i 4 c\u00f3 d\u1ea1ng 0300, ta ch\u01a1i c\u1eb7p 030 trong 3 h\u00f4m)<\/p>\n\n\n\n \u2013 \u0110i\u1ec1u ki\u1ec7n \u00e1p d\u1ee5ng<\/strong>: Ch\u1ec9 khi k\u1ebft qu\u1ea3 ng\u00e0y h\u00f4m \u0111\u00f3 ch\u1ec9 c\u00f3 1 l\u00f4 2 nh\u00e1y (kh\u00f4ng t\u00ednh c\u00e1c l\u00f4 2 nh\u00e1y k\u00e9p v\u00e0 l\u00f4 3 nh\u00e1y) th\u00ec m\u1edbi s\u1eed d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y \u0111\u01b0\u1ee3c (n\u1ebfu c\u00f3 2 con l\u00f4 2 nh\u00e1y tr\u1edf l\u00ean th\u00ec kh\u00f4ng s\u1eed d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y)<\/p>\n\n\n\n +) Sau khi ta t\u00ecm \u0111\u01b0\u1ee3c 1 con l\u00f4 2 nh\u00e1y. Ta g\u1ecdi con l\u00f4 2 nh\u00e1y l\u00e0 AB, s\u1ebd l\u1ed9n AB th\u00e0nh BA.<\/p>\n\n\n\n +) Ta x\u00e9t l\u00fd thuy\u1ebft b\u00f3ng d\u01b0\u01a1ng<\/strong> nh\u01b0 sau: 0-5, 1-6, 2-7, 3-8, 4-9.<\/p>\n\n\n\n +) G\u1ecdi C l\u00e0 b\u00f3ng c\u1ee7a A v\u00e0 G\u1ecdi D l\u00e0 b\u00f3ng B.<\/p>\n\n\n\n +) Ta s\u1ebd \u0111\u00e1nh 2 l\u00f4 BC, DA v\u00e0o ng\u00e0y ti\u1ebfp theo.<\/p>\n\n\n\n V\u00ed d\u1ee5<\/em>: H\u00f4m nay ta \u0111\u00e3 t\u00ecm \u0111\u01b0\u1ee3c l\u00f4 2 nh\u00e1y l\u00e0 AB=68. Ta l\u1ed9n th\u00e0nh BA= 86 v\u00e0 ta s\u1ebd \u0111\u00e1nh BC = 81 (1 b\u00f3ng c\u1ee7a 6) v\u00e0 \u0111\u00e1nh DA = 36 (3 b\u00f3ng c\u1ee7a 8) v\u00e0o ng\u00e0y ti\u1ebfp theo.<\/em><\/p>\n\n\n\n \u2013 Th\u1eddi gian nu\u00f4i<\/strong>: Ta \u0111\u00e1nh c\u1eb7p n\u00e0y Max 3 ng\u00e0y theo t\u1ef7 l\u1ec7 1: 3 : 6. N\u1ebfu tr\u00fang th\u00ec d\u1eebng<\/p>\n\n\n\n=> Nh\u01b0 v\u1eady ta c\u00f3 t\u1ea5t c\u1ea3 50 + 40 + 9 + 8=107 s\u1ed1 t\u01b0\u01a1ng \u1ee9ng 107 v\u1ecb tr\u00ed kh\u00e1c nhau.<\/strong><\/h4>\n\n\n\n
C\u00e1c ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 \u0111\u1ec1:<\/strong><\/h2>\n\n\n\n
1. Ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4:<\/strong><\/h2>\n\n\n\n
Ph\u01b0\u01a1ng ph\u00e1p 1: Kinh nghi\u1ec7m \u0111\u01a1n thu\u1ea7n<\/strong><\/h3>\n\n\n\n
V\u00ed d\u1ee5<\/em>:<\/h4>\n\n\n\n
Ph\u01b0\u01a1ng ph\u00e1p 2: L\u00f4 v\u1ec1 2 nh\u00e1y<\/strong><\/h2>\n\n\n\n
\u2013 C\u00e1ch soi c\u1ea7u MB:<\/h4>\n\n\n\n